Computational Thinking · End Term · Sep 2025 · AN

Useful Data has been mentioned above.

This data attachment is just for a reference & not for an evaluation.

A= Number of cities with the lowest Mathematics scores B = The highest marks in Mathematics

*

In the Line 6, if we replace the conditional statement by firstbict[key] < secondbict[key] , then the value of commondict will be {'n': 1, ‘i’: 1} In the Line 6, if we replace the conditional statement by firstbict[key] < seconddict[key] , 6406536029410, x then the value of commondict will be {'n': 3, i: 2}

1 2 pw NOW 10 tht 12 13 B=0 if(x.chemistry == y.Chemistry){ B=B+1 } if(x.Mathematics == Y.Mathematics) { B=B+tl } if(x.Physics == Y.Physics){ B=B+il } if(B == 1){ A=A4+1

[3, 2, 1, 5, 0, 4]

[3, 0, 2, 1, 4, 5]

[3, 2, 1, 0, 5, 4]

[3, 0, 1, 2, 5, 4]

B1 = 2, B2= 0

B1 = 1, B2= 2

B1 = 2, B2= 1

B1 = 2, B2= 2

No errors

['z', 'x']

['y', 'x', 'z']

['x', 'y']

['x', 'z', 'x']

Interchanging Line 5 and 8 will provide the correct result.

No error

**N** represents the maximum number of bills issued to a single customer.

**count** represents the number of bills in the dataset.

**A** represents the maximum number of bills issued to a single customer.

**N** represents the maximum number of bills issued to a single customer from the same shop.

**length(aList) >= length(keys(D))**

Foreach **a** in **aList, D[a] == a**

If **x** be the minimum element in **aList,** then **D[x] > x**

None of these

**i** scored at most 10 and at least 21 more marks in Physics than **j**

**j** scored at least 10 and at most 19 more marks in Physics than **i**

**i** scored at least 10 and at most 19 more marks in Physics than **j**

**j** scored at most 10 and at least 21 more marks in Physics than **i**