ms4001_2025T3_Q1_NA.pdf

Industry 4.0 · Quiz 1 · Sep 2025

Questions and published explanations below are available without starting a test. Some questions may not have a published solution yet.

Question 208 MCQ · 1.0 marks

Match Col A with Col B for landmark outcome of industrial era : [[IMAGE:94bcd0c5edd3bdbe_2_0]]

1.0:CNC, 2.0:Mass production, 3.0: Digitization, 4.0:Steam Engine
1.0:Steam Engine, 2.0:mass production, 3.0: digitization, 4.0:CNC
1.0:Mass production, 2.0:Steam Engine, 3.0: digitization, 4.0:CNC
1.0:Steam Engine, 2.0:mass production, 3.0: CNC, 4.0: Digitization

Published solution

**1. Recall the eras:** Industry 1.0 = steam engine (mechanization). Industry 2.0 = mass production (electricity, assembly lines). Industry 3.0 = automation (CNC, computers). Industry 4.0 = digitization (smart, connected systems). **2. Conclude:** 1.0: Steam Engine, 2.0: Mass production, 3.0: CNC, 4.0: Digitization. Answer: D — 1.0: Steam Engine, 2.0: Mass production, 3.0: CNC, 4.0: Digitization. A: **Incorrect:** Steam engine is 1.0 and digitization is 4.0; this mapping is reversed. B: **Incorrect:** CNC belongs to 3.0 and digitization to 4.0. C: **Incorrect:** Mass production is 2.0 and steam engine is 1.0. D: **Correct:** Matches all four eras correctly.

Question 209 MCQ · 1.0 marks

Identify the Industry 4.0 version of transportation.

IC engine
Electric car
Hyperloop

Published solution

**1. Concept:** Industry 4.0 means smart, connected, high-technology systems. **2. Compare:** IC engine is Industry 2.0/3.0 technology. An electric car is a modern but still conventional vehicle. A hyperloop is a new, highly automated and connected transport system. **3. Conclude:** The Industry 4.0 version of transportation is the hyperloop. Answer: C — Hyperloop. A: **Incorrect:** It is an older technology. B: **Incorrect:** It is a modern vehicle, but not the Industry 4.0 transport concept. C: **Correct:** The hyperloop is the advanced, smart transport system.

Question 210 MCQ · 1.0 marks

Select the layout(s) which do not require general supervision:

Product layout
Process layout
Group layout
Fixed position layout

A published solution is not available for this question yet.

Question 211 MCQ · 1.0 marks

Which of the following is an advantage of Process Layout?

Low material handling
Total production time per unit is small
Low training cost for the operators
It can accommodate high variety of products

Published solution

**1. Concept:** A process layout groups similar machines or functions together. It is flexible but has long, mixed routes. **2. Check:** Low material handling, short production time per unit and low training cost are advantages of a product layout, not of a process layout. Process layout needs skilled operators and has heavy movement of materials. **3. Conclude:** Its advantage is that it can handle a high variety of products. Answer: D — It can accommodate high variety of products. A: **Incorrect:** Process layout has high material handling because routes differ for each job. B: **Incorrect:** Process layout has long production time because jobs move between departments. C: **Incorrect:** Process layout needs skilled operators, so training cost is not low. D: **Correct:** Flexibility for many products is the main advantage of process layout.

Question 212 MCQ · 1.0 marks

Following is the layout from an aircraft manufacturing company. Identify the layout from the figure below. [[IMAGE:94bcd0c5edd3bdbe_3_1]]

Product layout
Process Layout
Group layout
Fixed position layout.

Published solution

**1. Concept:** In a fixed position layout, the large product stays in one place and workers, materials and equipment move to it. **2. Apply:** Aircraft are too large and complex to move through stations, so assembly takes place in a fixed location. **3. Conclude:** The layout is a fixed position layout. Answer: D — Fixed position layout. A: **Incorrect:** A product layout moves work along a line of stations. B: **Incorrect:** A process layout groups similar machines, not one large product. C: **Incorrect:** A group layout forms cells for families of parts. D: **Correct:** Large products like aircraft stay in one place during assembly.

Question 213 MCQ · 1.0 marks

Select the appropriate layout for Quadrants A, B, D in the following figure: [[IMAGE:94bcd0c5edd3bdbe_4_2]]

A: Group layout, B: Product layout , D: Process layout
A: Product layout, B: Process layout , D: Group layout
A:Process layout, B:Group layout , D: Product layout

Published solution

**1. Concept:** Layout depends on variety and volume. High variety with low volume suits a process layout. Low variety with high volume suits a product layout. Between them is the group layout. **2. Map the quadrants:** - A (high variety, low volume): process layout. - B (high variety, high volume): group layout. - D (low variety, high volume): product layout. **3. Conclude:** A: Process, B: Group, D: Product. Answer: C — A: Process layout, B: Group layout, D: Product layout. A: **Incorrect:** A needs a process layout, and D needs a product layout. B: **Incorrect:** A is not a product layout; B is not a process layout. C: **Correct:** A: Process, B: Group, D: Product matches the variety-volume chart.

Question 214 MCQ · 1.0 marks

Which of the following is an advantage of Product Layout?

Small in-process inventory
It can accommodate high variety of products
High utilization of machines
Low investment

Published solution

**1. Concept:** A product layout arranges machines in the order of operations, so work flows continuously from one station to the next. **2. Check:** This gives small in-process inventory. It handles only low variety, needs high investment, and machine utilization depends on balancing the line (some stations sit idle). **3. Conclude:** The advantage is small in-process inventory. Answer: A — Small in-process inventory. A: **Correct:** Continuous flow keeps work-in-process low. B: **Incorrect:** High variety is an advantage of a process layout. C: **Incorrect:** Utilization depends on line balancing and is not guaranteed to be high. D: **Incorrect:** A product layout needs high investment in dedicated equipment.

Question 215 MCQ · 1.0 marks

The Production rate of an assembly line is determined by its

Slowest station
Fastest station
Idle station
None of these

Published solution

**1. Concept:** In an assembly line, every unit passes through all stations. The line can only move as fast as its slowest station (the bottleneck). **2. Conclude:** The production rate is set by the slowest station. Answer: A — Slowest station. A: **Correct:** The bottleneck sets the rate of the line. B: **Incorrect:** Faster stations must wait for the slowest one. C: **Incorrect:** An idle station does not set the rate. D: **Incorrect:** The slowest station is the answer.

Question 216 MSQ · 1.0 marks

Select the correct statements from below:

Optimal solution in a facility location problem using Euclidean method will result in a region
Optimal solution in a facility location problem using Euclidean method rarely matches the center of gravity
Optimal solution in a facility location problem using Euclidean method will result in a point
Optimal solution in a facility location problem using Euclidean method matches the center of gravity in not of the cases

Published solution

**1. Concept:** In the Euclidean (straight-line distance) single-facility location problem, we minimize the total weighted straight-line distance. The solution is a single point. **2. Compare with center of gravity:** The center of gravity minimizes the weighted squared distance, which is a different objective. So the two usually do not coincide, and only rarely match. **3. Check the options:** - Region: false, the solution is a point. - Rarely matches the center of gravity: true. - Result is a point: true. - 'Matches in none of the cases': false, since they sometimes match (for example, with one demand point). Answer: B, C — the optimal solution is a point and rarely matches the center of gravity. A: **Incorrect:** The optimal solution is a single point, not a region. B: **Correct:** The Euclidean optimum and the center of gravity minimize different objectives, so they rarely match. C: **Correct:** The Euclidean solution is a single point. D: **Incorrect:** They can match in some special cases, so 'none of the cases' is too strong (the wording of this option is also unclear).

Question 217 MSQ · 1.0 marks

Identify the examples for Offshoring from the list below:

Micron Technology, a US based semiconductor giant, setting up a Supply Chain Analytics team, in India.
Micron signs an agreement with Taiwan based TSMC Co., to manufacture sillicon wafer for their ICs.
Western Australia’s electricity network agency assigns Tata Consultancy Services at Pune, to support it with an overhaul of its legacy IT systems, aimed at delivering cheaper and more reliable power.
Tata Motors assigns the manufacturing of its braking system to TACO group.

A published solution is not available for this question yet.

Question 218 NAT · 1.0 marks

A factory works for two 8-hour shifts each day and produces a total of 30,000 electric bulbs using a set of workstations. There are 8 activities required to manufacture the bulb, such that the sum of all activity times is equal to 12 seconds. Answer the given subquestions:

What is the cycle time (in seconds) at any workstations (round your answer to one decimal e.g. if your answer is 1.89 then enter your answer as 1.9)

Published solution

**1. Given:** Two 8-hour shifts, so total time per day \(=2\times8\times3600=57{,}600\) s. Output \(=30{,}000\) bulbs. **2. Formula:** Cycle time \(=\frac{\text{available time}}{\text{output}}\). **3. Calculate:** \[ CT=\frac{57600}{30000}=1.92\approx1.9\text{ s} \] Answer: \(1.9\) seconds.

Question 219 NAT · 1.0 marks

What is the theoretical minimum number of workstations required?

Published solution

**1. Formula:** Theoretical minimum number of workstations \(=\frac{\sum t}{CT}\), rounded up. **2. Calculate:** \(\sum t=12\) s and \(CT=1.92\) s: \[ \frac{12}{1.92}=6.25\;\Rightarrow\;7 \] **3. Conclude:** We round up because stations cannot be fractional. Answer: \(7\).

Question 220 NAT · 1.0 marks

Consider the following precedence diagram. It has 12 activities. The numbers in blue and withing the braces denote the respective activity times in minute. [[IMAGE:94bcd0c5edd3bdbe_7_3]] Based on the above data, answer the given subquestions.

What is the minimum cycle time of the system (answer in minutes without the unit e.g. if your answer is 10 min enter as 10)?

Published solution

**1. Concept:** The cycle time of a line cannot be smaller than the longest single activity, because an activity cannot be split between stations. **2. Activity times (min):** 5, 4, 12, 9, 10, 8, 7, 6, 9, 3, 5, 7. The longest is activity 3 with 12 min. **3. Conclude:** The minimum cycle time is 12 min. Answer: \(12\).

Question 221 NAT · 1.0 marks

What is the maximum cycle time of the system?

Published solution

**1. Concept:** The maximum cycle time occurs when all activities are done at a single workstation, so it equals the total work content. **2. Add the times:** \[ 5+4+12+9+10+8+7+6+9+3+5+7=85 \] **3. Conclude:** The maximum cycle time is 85 min. Answer: \(85\).

Question 222 MCQ · 1.0 marks

The factory works for one 8-hour shifts each day. Is it possible to achieve an output of 32 units/day

Published solution

**1. Given:** One 8-hour shift \(=480\) min. Target output \(=32\) units. **2. Required cycle time:** \[ CT=\frac{480}{32}=15\text{ min} \] **3. Check feasibility:** The cycle time must be at least 12 min (longest activity). 15 min is above 12, so it is feasible. The layout with stations (1,2)=9, (3)=12, (4)=9, (5)=10, (6,7)=15, (8,9)=15, (10,11,12)=15 has a largest station time of 15 min. **4. Conclude:** Yes, 32 units per day is possible. Answer: B — Yes. A: **Incorrect:** A cycle time of 15 min is at least the longest activity (12 min), so it is possible. B: **Correct:** Required cycle time is 15 min, which is achievable.

Question 223 NAT · 1.0 marks

What is the balance delay of the following layout (round it to two decimals) (1,2) -> (3) -> (4) -> (5) -> (6,7) -> (8,9) -> (10,11,12) (Instruction: if your answer is 14.52%, enter as 14.5)

Published solution

**1. Station times (min):** (1,2): \(5+4=9\); (3): 12; (4): 9; (5): 10; (6,7): \(8+7=15\); (8,9): \(6+9=15\); (10,11,12): \(3+5+7=15\). **2. Find n and CT:** There are \(n=7\) stations. The cycle time is the largest station time, \(CT=15\) min. Total work content \(\sum t=85\). **3. Balance delay:** \[ D=\frac{nCT-\sum t}{nCT}\times100=\frac{105-85}{105}\times100=19.05\% \] Answer: \(19.05\) (about \(19.0\%\)). **Review note:** In the given station order, activity 5 comes before activity 6, but 6 must finish before 5 according to the diagram. The calculation below uses the station times exactly as the question gives them, which matches the supplied key.

Question 224 NAT · 1.0 marks

What is the efficiency of the given layout? (Instruction: Round off to two decimals without percentage sign. If your answer is 70.51%, enter as 70.5)

Published solution

**1. Use the station data:** \(n=7\), \(CT=15\) min, \(\sum t=85\) min. **2. Efficiency:** \[ \text{Efficiency}=\frac{\sum t}{nCT}\times100=\frac{85}{105}\times100=80.95\% \] Answer: \(80.95\). **Review note:** In the given station order, activity 5 comes before activity 6, but 6 must finish before 5 according to the diagram. The calculation below uses the station times exactly as the question gives them, which matches the supplied key.

Question 225 MSQ · 1.0 marks

There are four demand points at A(1,2), B(2,3), C(3,5), D(4,1). The respective demand at these points are 7, 1, 3, 5. Select the optimal location based on cross-median approach.

(2,2)
(3,2)
(2.5,2)
(2,3)

Published solution

**1. Concept:** The cross-median method finds the median location separately for x and y, weighted by demand. Total demand \(=7+1+3+5=16\), so half is 8. **2. x-coordinate:** Sort by x and add demand: x=1 (7), x=2 (cumulative 8), x=3 (11), x=4 (16). Cumulative demand reaches exactly 8 at x=2, so any x between 2 and 3 is optimal. **3. y-coordinate:** Sort by y: y=1 (5), y=2 (cumulative 12), y=3 (13), y=5 (16). Cumulative demand first passes 8 at y=2, so the optimal y is 2. **4. Check options:** Points with \(2\le x\le3\) and \(y=2\) are optimal: (2,2), (3,2), (2.5,2). The point (2,3) has \(y=3\), which is not optimal. Answer: A, B, C — (2,2), (3,2) and (2.5,2). A: **Correct:** x=2 is in the median range and y=2 is the median, so it is optimal. B: **Correct:** x=3 is the end of the median range and y=2, so it is optimal. C: **Correct:** x=2.5 is in the median range and y=2, so it is optimal. D: **Incorrect:** y=3 is not the weighted median of y (it is 2), so it is not optimal.

Question 226 NAT · 1.0 marks

Calculate the Euclidean distance between two machines located at the coordinates A(5,10) and B(2,6) in a shop floor. [round off your answer to one decimal]

Published solution

**1. Formula:** Euclidean distance \(=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\). **2. Substitute:** \(A(5,10)\), \(B(2,6)\): \[ d=\sqrt{(5-2)^2+(10-6)^2}=\sqrt{9+16}=\sqrt{25}=5 \] Answer: \(5.0\).